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NECO 2017 Mathematics OBJ And Essay Answer – June/July Expo

Wednesday 14th June 2017
Paper III: OBJ – General Mathematics – 10am – 11:45am

Essay – General Mathematics – 12pm – 2:30pm

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VERIFIED MATHEMATICS OBJ
1-10 CCAADDEECE
11-20 EEBABAADCC
21-30 CBEEDABDDD
31-40 BCCCDDCADE
41-50 BDCDDCDECD

51-60 BCDCAEDCDD

MATHEMATICS -Answers

Use This No1 pls is more accurate

1)
tabulate
Number –
5932
*6141
num
3679
*3113
den
Log
3.7732
3.7882
7.5612
3.5657
3.4931
7.0588
anti log
7.5612
7.0588 /0. 5024 /3=0. 1675
anti log

=1471 *10

2)
a = 3, b = 20 , C = -7
Sum is
( α/1 + 1/β + β/1 + 1/ α) Note α means Alpha
α^2 β + β^2 + α + β / α β
= -7 /3 ( -20 /3) + ( -20/3) = 140 /9 – 20/3 / -7 /3
( Note / means
Divided)
= 80 /9 x -3/7 = -80 /21
Product br /> -7/3 + 2 + 1 /-7/3 = -7/3 + 2 /1 –
3/7
= -49 + 42-9 /21
= -16 /21
x ^2 – ( sum ) x + product= 0
x ^2 – 80/21 x + ( -16/21 ) = 0
Final Answer : 21x ^2 – 80 x – 16 = 0

.

3a )
P =100I /RT =100 30, 000 /43
P =N 250 , 000 .
NO ( 3 a )
I=# 30, 000
R =3%
T= 4YRS
P =100 X 1/RT =100 X 30, 000/3 X 4
=25, 000#
( 3B )
#7000 T0 FRANCS
8FRANS = # 1
?FRANCS =7000
CROSS MULTIPLY
=#56 , 000 FRANCS
SPENDING 49, 400 FRANCS
56, 000-49 , 400 = 6600
CONVERTING 6, 600 FRANCS TO # AT 10 FRANCS
TO 1#
10 FRANCS—– 1#
6600 FRANCS—?#

=6, 600/10 X 1

5)
tabulate
Mark- 21 -25, 26-30, 31-35 , 36-40 , 41 -45, 46 -50
F- 6 , 8, 12, 4 , 6, 4=40
X – 23, 28, 33, 38 , 43 , 48
FX – 138 , 224 , 396 , 152 , 258 , 192 =1360
Class Boundaries – 20. 5-20. 5,
25. 5-30. 5, 35 .5-40 .50, 40. 5-45. 5
5i )
MEAN
( X )= EFX /EF= 1360/40 =34
MODE
L1+ [ Fm-Fa /2 fm-fa-fb ] c
=30. 5+ [ 12-8/2( 12 ) -8-4] 5
=30. 5+ [ 4/12] 5
=30. 5+ 1. 67
=32. 17
7b)
L = ar ^n-1
729/3 = 3/3 x 3^n-1
243 = 3 ^n-1
3^5 = 3^-1
5 = n-1
N = 5+ 1
= 6
Sn = a ( r ^-1) /r -1 = 3 ( 3^6 – 1) /3-1
Sn = 3( 729 -1 ) /2
S 6 = 3 x 728 /2
S 6 = 1092
7c )
3x ^3/3 + x | 2, 1
( 2^3 + 2) – ( 1^3 + 1)
( 8+ 2) – ( 1+ 1)
= 8

 

Confirmed Mathematics Obj

1 – 10 CCDADDEECE
11 – 20 ECAABA–CB
21 – 30 BB – – – – – – -E
31- 40 BCCCDDCADE
41- 50 BDCDDCDECD
51- 60 BCDCAEDCDD

 

VERIFIED MATHEMATICS OBJ
BY GENERALBAZE.COM
1=E
2=C
3=A
4=A
5=D
6=D
7=E
8=E
9=C

10=E

11
12
13
14
15
16
17
18
19

20

21
22
23
24
25
26
27
28
29

30

31B
32C
33C
34C
35D
36D
37C
38A
39D

40E

41=B
42=D
43=C
44=D
45=D
46=C
47=D
48=E
49=C

50=D

51=B
52=C
53=D
54=C
55=A
56=E
57=D
58=C
59=D
60=D

 

NO (3a)

I=#30,000
R=3%
T= 4YRS

P=100 X 1/RT =100 X 30,000/3 X 4
=25,000#

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(3B)
#7000 T0 FRANCS

8FRANS= #1
?FRANCS =7000

CROSS MULTIPLY
=#56,000 FRANCS

SPENDING 49,400 FRANCS

56,000-49,400 = 6600
CONVERTING 6,600 FRANCS TO # AT 10 FRANCS TO 1#
10 FRANCS—– 1#
6600 FRANCS—?#
=6,600/10 X1

 

7b)
L = ar^n-1
729/3 = 3/3 x 3^n-1
243 = 3^n-1
3^5 = 3^-1
5 = n-1
N = 5+1
= 6

Sn = a(r^-1)/r-1 = 3(3^6 – 1)/3-1
Sn = 3( 729 -1)/2
S6 = 3 x 728/2
S6 = 1092

7c)
3x^3/3 + x | 2,1
(2^3 + 2) – (1^3+1)
(8+2) – (1+1)
= 8‎

1)
tabulate
Number-
5932
6141
num
3679
*3113
den
Log
3.7732
3.7882
7.5612
3.5657
3.4931
7.0588
anti log
7.5612
7.0588/0.5024/3=0.1675
anti log
=1471
10

I = PRT/100, p=N15000 R=10% and I=3years
A = P+ I
where I = 15000103/100=N4500
A=4500+15000 =N19500

1b)
I = PRT/100, p=N15000 R=10% and I=3years
A = P+ I
where I = 15000103/100=N4500
A=4500+15000 =N19500

==================================

2a)
using sine rule
b/sin20 = 6/sin30
bsin30 = 6sin120
b 6sin120/sin30
b = 6×0.2511/0.4540
b = 5.7063/0.4540
b = 12.57 ≠ 12.6cm

2bi)
the diagram is euivalent triangles.
where
|AX|/|BC| = |BY|/|AC| = |XY|/|YC|
XY = 9, BY = 7
YC = 18-7=11
9/11 = 7/|AC|
9|AC| = 77
|AC| = 77/9
|AC| = 8cm

2bii)
XY/AB = BY/AC
9/|AB| = 7/8.6
|AB| = 9×8.6/7
|AB| = 11cm

==================================

2a)
using sine rule
b/sin20 = 6/sin30
bsin30 = 6sin120
b 6sin120/sin30
b = 6×0.2511/0.4540
b = 5.7063/0.4540
b = 12.57 ≠ 12.6cm

2bi)
the diagram is euivalent triangles.
where
|AX|/|BC| = |BY|/|AC| = |XY|/|YC|
XY = 9, BY = 7
YC = 18-7=11
9/11 = 7/|AC|
9|AC| = 77
|AC| = 77/9
|AC| = 8cm

2bii)
XY/AB = BY/AC
9/|AB| = 7/8.6
|AB| = 9×8.6/7
|AB| = 11cm

Use This No1 pls is more acurate
1)
tabulate
Number-
5932
*6141
num
3679
*3113
den
Log
3.7732
3.7882
7.5612
3.5657
3.4931
7.0588
anti log
7.5612
7.0588/0.5024/3=0.1675
anti log

=1471*10

3a)
P=100I/RT=10030,000/43

P=N250,000

5)
tabulate
Mark- 21-25,26-30,31-35,36-40,41-45,46-50
F- 6,8,12,4,6,4=40
X- 23,28,33,38,43,48
FX- 138,224,396,152,258,192=1360
Class Boundaries- 20.5-20.5, 25.5-30.5,35.5-40.50,40.5-45.5
5i)
MEAN
(X)=EFX/EF=1360/40=34
MODE
L1+[Fm-Fa/2fm-fa-fb] c
=30.5+[12-8/2(12)-8-4] 5
=30.5+[4/12] 5
=30.5+1.67
=32.17

a = 3, b = 20, C = -7
Sum is
(α/1 + 1/β + β/1 + 1/ α) Note α means Alpha
α^2 β + β^2 + α + β / α β
= -7/3 (-20/3) + (-20/3) = 140/9 – 20/3 / -7/3 (Note / means
Divided)
= 80/9 x -3/7 = -80/21
Product:
-7/3 + 2 + 1/-7/3 = -7/3 + 2/1 – 3/7
= -49+42-9/21
= -16/21
x^2 – (sum)x + product= 0
x^2 – 80/21x + (-16/21) = 0
Final Answer : 21x^2 – 80x – 16 = 0

41-50 BDCDDCDECD
51-60 BCDCAEDCDD

MATHEMATICS-Answers
Use This No1 pls is more acurate
1)
tabulate
Number-
5932
*6141
num
3679
*3113
den
Log
3.7732
3.7882
7.5612
3.5657
3.4931
7.0588
anti log
7.5612
7.0588/0.5024/3=0.1675
anti log

=1471*10

 

2)
a = 3, b = 20, C = -7
Sum is
(α/1 + 1/β + β/1 + 1/ α) Note α means Alpha
α^2 β + β^2 + α + β / α β
= -7/3 (-20/3) + (-20/3) = 140/9 – 20/3 / -7/3 (Note / means
Divided)
= 80/9 x -3/7 = -80/21
Product:
-7/3 + 2 + 1/-7/3 = -7/3 + 2/1 – 3/7
= -49+42-9/21
= -16/21
x^2 – (sum)x + product= 0
x^2 – 80/21x + (-16/21) = 0
Final Answer : 21x^2 – 80x – 16 = 0
.

======================
3a)
P=100I/RT=10030,000/43

P=N250,000

5)
tabulate
Mark- 21-25,26-30,31-35,36-40,41-45,46-50
F- 6,8,12,4,6,4=40
X- 23,28,33,38,43,48
FX- 138,224,396,152,258,192=1360
Class Boundaries- 20.5-20.5, 25.5-30.5,35.5-40.50,40.5-45.5
5i)
MEAN
(X)=EFX/EF=1360/40=34
MODE
L1+[Fm-Fa/2fm-fa-fb] c
=30.5+[12-8/2(12)-8-4] 5
=30.5+[4/12] 5
=30.5+1.67
=32.17

 

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