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2018 NECO Gce Mathematics Obj & Theory Answer Nov/Dec

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Welcome to the Real and Verified NECO GCE Mathematics Questions and Answer – Nov/Dec 2018 Expo Runz. Verified National Examination Council (Private) November/December GCE 2018 Mathematics Obj, Essay and Maths Answer Page

READ ALSO :   2018 NECO Physics Theory/Essay/Obj Questions And Answers

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Answers Posted Free Below

NECO VERIFIED MATHS OBJ
1 CCBEAEBECE
11 AADCEECABB
21 CBBAACEBAD
31 CAABEEBCAD
41 ECCECEDDAC
51 ACABCCCCCB

NECO GCE MATHS

(1)
TABULATE:
No| Log
3081| 3.4887
0.775 | 1.8893
0.456 | 1. 6589
| UNDER Log
| 3.4887
| 1. 5482
| 3.9405
| 0.9851
Square root of 4/3081/0.775.0456
Antilog = 9663
= 9.663
= 2.9

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(2a)
1101₂ = 2x + 1
1 x 2² + 0 x 2¹+ 1 x 2º = 2x + 1
8 + 4 + 1 = 2x +1
13 – 2x
X = 12/2 = 6

(2b)
Sin x = 12/13 = 0.9231
Z = sin-¹ 0.9231 = 67.4º
Therefore 3 sin x + ½ cos x
= 3 sin 67.4 + ½ cos 67.4
= 3 x 0.9232 + ½ x 0.3843
= 7.7696 + 0.1921

(3a)
PQ x 90º [angle in a semicircle]
QPO = 90º – 62 [ angle in a triangle]
= 28º
Therefore POZ = 28º [alternative angles]
(ii)
PXZ = ½ x 28º = 14º [angle at center is twice angle at cirumfeence]

(3b)
6/5 + 3/x+3 – 9/5(x+3)
= 6 (x+3) + 3 (5) – 9/5(x+3)
= 6x + 18 + 15 – 9/5 (x+3)
= 6x + 24/5(x+3)
= 6(x+4)/5(x+3)

NECO VERIFIED MATHS OBJ
1 CCBEAEBECE
11 AADCEECABB
21 CBBAACEBAD
31 CAABEEBCAD
41 ECCECEDDAC
51 ACABCCCCCB
===============
NECO GCE MATHS

(1)
TABULATE:
No| Log
3081| 3.4887
0.775 | 1.8893
0.456 | 1. 6589
| UNDER Log
| 3.4887
| 1. 5482
| 3.9405
| 0.9851
Square root of 4/3081/0.775.0456
Antilog = 9663
= 9.663
= 2.9

(2a)
1101₂ = 2x + 1
1 x 2² + 0 x 2¹+ 1 x 2º = 2x + 1
8 + 4 + 1 = 2x +1
13 – 2x
X = 12/2 = 6

(2b)
Sin x = 12/13 = 0.9231
Z = sin-¹ 0.9231 = 67.4º
Therefore 3 sin x + ½ cos x
= 3 sin 67.4 + ½ cos 67.4
= 3 x 0.9232 + ½ x 0.3843
= 7.7696 + 0.1921

(3a)
PQ x 90º [angle in a semicircle]
QPO = 90º – 62 [ angle in a triangle]
= 28º
Therefore POZ = 28º [alternative angles]
(ii)
PXZ = ½ x 28º = 14º [angle at center is twice angle at cirumfeence]

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(3b)
6/5 + 3/x+3 – 9/5(x+3)
= 6 (x+3) + 3 (5) – 9/5(x+3)
= 6x + 18 + 15 – 9/5 (x+3)
= 6x + 24/5(x+3)
= 6(x+4)/5(x+3)

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